C++ does not allow polymorphism for methods based on their return type. However, when overloading an operator this seems possible.
Does anyone know why? I thought operators are handled like methods internally.
Edit: Here's an example:
struct func {
operator string() { return "1";}
operator int() { return 2; }
};
int main( ) {
int x = func(); // calls int version
string y = func(); // calls string version
double d = func(); // calls int version
cout << func() << endl; // calls int version
}