Why is my XSLT fragment causing an error?

Question

I am trying to use the below code to check if my variable contains the word NOT_INTERFACED. So I am using the ends-with function.

But if it does I want to print the remaining word minus NOT_INTERFACED.

But I am getting an error, my java program is calling this template however I get an exception ends-with not found.

Am I doing something wrong syntax wise ?

<xsl:choose>
  <xsl:when test="ends-with($ID_FO, 'NOT_INTERFACED')">
    <xsl:value-of select="substring-before($ID_FO, 'NOT_INTERFACED')"/>
  </xsl:when>
  <xsl:otherwise>
    <xsl:value-of select="$ID_FO"/>
  </xsl:otherwise>
</xsl:choose>

and the error is

COULD NOT FIND FUNCTION ENDS WITH. LOCATION: unknown
java.lang.NullPointerException

Answer 1

EDIT: See my comment below,

I checked the XPATH 1.0 documentation and it does not include an ends-with function. You'll have to do the substring method I detailed below--that is if you are using XSLT 1.0 (which uses XPATH 1.0)

EDIT 2: Just so my comment has some nice syntax highlighting:

<xsl:when test="substring($ID_FO, string-length($ID_FO)-14) = '_NOT_INTERFACED'">

Answer 2

XSLT parsers are case sensitive - try using this:

<xsl:choose>
    <xsl:when test="ends-with($ID_FO, 'NOT_INTERFACED')">
      <xsl:value-of select="substring-before($ID_FO, 'NOT_INTERFACED')"/>
     </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="$ID_FO"/>
    </xsl:otherwise>
</xsl:choose>

Also you had forgotten to close the xsl:when element after the test attribute.

Answer 3

I've already posted it as a comment in my answer over at your other question. Replace your entire <xsl:choose> construct with this one-liner:

<xsl:value-of select="
  substring-before(concat($ID_FO, 'NOT_INTERFACED'), 'NOT_INTERFACED')
" />

You are still not clear whether your string contains or ends with 'NOT_INTERFACED'.

If it ends with the substring you want to get rid of, use the above. If it contains it, you have your answer in the other question. I suggest having a second look there.