C# ThreadStart with parameters

Question

How is it possible to start a thread with parameters in C#

Answer 1

Yep :

Thread t = new Thread (new ParameterizedThreadStart(myParamObject));
t.Start (myUrl);

Answer 2

One of the 2 overloads of the Thread constructor takse a ParameterizedThreadStart delegate which allows you to pass a single parameter to the start method. Unfortunately though it only allows for a single parameter and it does so in an unsafe way because it passes it as object. I find it's much easier to use a lambda expression to capture the relevant parameters and pass them in a strongly typed fashion.

Try the following

public Thread StartTheThread(SomeType param1, SomeOtherType param2) {
  var t = new Thread(() => RealStart(param1, param2));
  t.Start();
  return t;
}

private static void RealStart(SomeType param1, SomeOtherType param2) {
  ...
}

Answer 3

class Program
{
    static void Main(string[] args)
    {
        Thread t = new Thread(new ParameterizedThreadStart(ThreadMethod));

        t.Start("My Parameter");
    }

    static void ThreadMethod(object parameter)
    {
        // parameter equals to "My Parameter"
    }
}

Answer 4

Use ParameterizedThreadStart.

Answer 5

Use ParametrizedThreadStart.

Answer 6

You could use a ParametrizedThreadStart delegate:

string parameter = "Hello world!";
Thread t = new Thread(new ParameterizedThreadStart(MyMethod));
t.Start(parameter);

Answer 7

The ParameterizedThreadStart takes one parameter. You can use that to send one parameter, or a custom class containing several properties.

Another method is to put the method that you want to start as an instance member in a class along with properties for the parameters that you want to set. Create an instance of the class, set the properties and start the thread specifying the instance and the method, and the method can access the properties.

Answer 8

Thread thread = new Thread(Work);
thread.Start(Parameter);

private void Work(object param)
{
    string Parameter = (string)param;
}

The parameter type must be an object.

Answer 9

You can use the BackgroundWorker RunWorkerAsync method and pass in your value.