Windows Batch Search and Replace Question

Question

I have a small batch file to search and replace within a batch file. I am having difficulty removing things (eg replacing some text with a null value). Am sure it is simple but not found anything by searching!

This is the file:

Where you see xxxxx and yyyyy is where I need a blank!

Cheers.

@echo off
setlocal enabledelayedexpansion

if exist %~n1.bugs%~x1 del %~n1.bugs%~x1

if not exist "%1" (echo this file does not exist...)&goto :eof

set FIND_LOGO_1_DATA=logo_data_0 101
set FIND_LOGO_2_DATA=logo_data_0 102
set FIND_LOGO_3_DATA=logo_data_0 103
set FIND_LOGO_4_DATA=logo_data_0 104
set FIND_LOGO_5_DATA=logo_data_0 107
set FIND_LOGO_6_DATA=logo_data_0 108
set FIND_LOGO_7_DATA=logo_data_0 109
set FIND_LOGO_8_DATA=logo_data_0 110
set FIND_LOGO_9_DATA=logo_data_0 105
set FIND_LOGO_10_DATA=logo_data_0 106


for /f "tokens=* delims=" %%a in (%1) do (

   set write=%%a
   if "%%a"=="logo_0 2" set write=xxxxx
   if "%%a"=="logo_0 1" set write=yyyyy
   if "%%a"=="%FIND_LOGO_1_DATA%" set write=logo_0 1
   if "%%a"=="%FIND_LOGO_2_DATA%" set write=logo_1 1
   if "%%a"=="%FIND_LOGO_3_DATA%" set write=logo_2 1
   if "%%a"=="%FIND_LOGO_4_DATA%" set write=logo_3 1
   if "%%a"=="%FIND_LOGO_5_DATA%" set write=logo_4 1
   if "%%a"=="%FIND_LOGO_6_DATA%" set write=logo_5 1
   if "%%a"=="%FIND_LOGO_7_DATA%" set write=logo_6 1
   if "%%a"=="%FIND_LOGO_8_DATA%" set write=logo_7 1
   if "%%a"=="%FIND_LOGO_9_DATA%" set write=logo_8 1
   if "%%a"=="%FIND_LOGO_10_DATA%" set write=logo_9 1


   (echo !write!)>>%~n1.bugs%~x1
)

Answer 1

If I'm seeing this correctly, then you just want to output a blank line in the two cases where you currently have xxxxx and yyyyy, right?

If that's the case, then it's actually very easy. You just have to set write to nothing:

set write=

and alter the line where you echo that variable in the following way:

echo.!write!

This will cause echo to output an empty line if write is empty and suppress the "ECHO is off." message (also documented here).