Color.ToArgb relation between 5046311 and 14221235 ??

Question

the form backcolor is 14221235 , but when i set the customcolor in colordialog to equal the form backcolor, it sets it to 5046311 !!! what is the problem?

this is how i am getting the background color:

get_background = Str(Abs(Form1.BackColor.ToArgb))

the reason i am turning it into a string is because i will feed it into a string which has "32498239, 234234234, 23423234, 32234432432, 423324234"

then i take this string and put it in customcolors like this. btw this piece of code works fine:

Dim numberStrings = My.Settings.mytext1.Split(","c).Select(Function(x) x.Trim())
ColorDialog1.CustomColors = numberStrings.Select(Function(x) CInt(x)).ToArray()

a user below mentioned that toargb takes into account the opacity. this is an excellent point indeed, and i want to clarify that i DO NOT need the opacity. how would i do toargb without taking into opacity?

Answer 1

The 32-bit result from .ToArgb() contains not just the three visible color components (red, green and blue) but also the alpha component, which is essentially opacity. This is a pure guess on my part, but I think the ColorDialog is just used for picking RGB values, so when you set the color to the form's BackColor, the dialog just ignores the alpha component (or sets it to zero), which is why you end up getting a different number from the .ToArgb() method.

Note: this is just speculation on my part. It would help if you posted a code sample that demonstrates the specific problem.

Answer 2

I don't really understand the question. You want to set the custom color dialog CustomColor property to (the form's backcolor) r + g + b components? Not sure why you would do that, you can always just get the form's backcolor, set the Alpha value to 255 and then set the result to the CustomColor property:

Color c = Color.FromArgb( 255, form1.BackColor );
myColorDlg.CustomColor = c;

Answer 3

Or just use form1.BackColor.ToArgb() & 0xFFFFFF (if you want the integer value).

Answer 4

this is what you want

Microsoft.VisualBasic.RGB(Me.BackColor.R, Me.BackColor.G, Me.BackColor.B).ToString

Answer 5

If you are asking for ARGB (A = Alpha) then you are asking for the opacity information. Instead you could use the R, G, B Properties of Color Independently.

Answer 6

You could use Color.FromArgb(255, me.BackColor).ToArgb() in order to get the ARGB value of the same color with 100% opacity.