BASH copy all files except one.

Question

I would like to copy all files out of a dir except for one name Default.png. It seems that there are a number of ways to do this. What seems the most effective to you?

Answer 1

Should be as follows:

cp -r !(Default.png) /dest

If copying to a folder nested in the current folder (called example in the case below) you need to omit that directory also:

cp -r !(Default.png|example) /example

Answer 2

I'd just do cp srcdir/* destdir/ ; rm destdir/Default.png unless the files are big. Otherwise use e.g.

find srcdir -type f/ |grep -v Default.png$ |xargs -ILIST cp LIST destdir/

Answer 3

Simple, if src/ only contains files:

find src/ ! -name Default.png -exec cp {} dest/ +

If src/ has sub-directories, this omits them, but does copy files inside of them:

find src/ -type f ! -name Default.png -exec cp {} dest/ +

If src/ has sub-directories, this does not recurse into them:

find src/ -type f -maxdepth 1 ! -name Default.png -exec cp {} dest/ +

Answer 4

rsync has been my cp/scp replacement for a long time :

rsync -av from/ to/ --exclude=Default.png

Answer 5

cp `ls | grep -v Default.png` destdir