REVISION (12-Sep-2009 ~2:20 PM EST):
So, I made this suggestion last night on the basis that Enum.GetValues returns an Array, and I thought that Array implements IEnumerable<T>:
I believe you can construct a
List<T> passing any IEnumerable<T>
as a parameter into the constructor.
So you should be able to just do this:
List<SomeEnum> values = new List<SomeEnum>(Enum.GetValues(typeof(SomeEnum)));
However, GordonG quite promptly replied to my answer indicating that it doesn't compile. (Ordinarily I would test my answer, but I was at a computer without any development tools at the time and was also feeling quite [unreasonably] sure of myself.)
After some downvotes and heavy soul-searching I resolved to get to the bottom of this matter (after a good night's sleep). Turns out, according to Microsoft's documentation on the Array class here, that Array does implement IEnumerable<T>, but only at run time (so, not at compile time--hence the failure to compile). This, in hindsight, makes sense: Enum.GetValues is not a generic method, and so it cannot know what sort of generic collection to return beforehand. (At least that's how I understand it.)
Anyway, what this all means is that you can legally cast an Array to an IEnumerable<T> provided that you get your type right. And so, at last I can present my final answer, which is really the same as my original answer but with a simple cast thrown in to make everything legal:
// splitting into two lines just for readability's sake
List<SomeEnum> values;
values = new List<SomeEnum>((IEnumerable<T>) Enum.GetValues(typeof(SomeEnum)));
Of course, in retrospect, GordonG wasn't dead set on getting a List<T>, which means his own answer of casting to SomeEnum[] is really just as good.