How to find a URL from a content by PHP?

Question

need a simply preg_match, which will find "c.aspx" (without quotes) in the content if it finds, it will return the whole url. As a example

$content = '<div>[4]<a href="/m/c.aspx?mt=01_9310ba801f1255e02e411d8a7ed53ef95235165ee4fb0226f9644d439c11039f%7c8acc31aea5ad3998&amp;n=783622212">New message</a><br/>';

now it should preg_match "c.aspx" from $content and will give a output as

"/m/c.aspx?mt=01_9310ba801f1255e02e411d8a7ed53ef95235165ee4fb0226f9644d439c11039f%7c8acc31aea5ad3998&n=783622212"

The $content should have more links except "c.aspx". I don't want them. I only want all url that have "c.aspx".

Please let me know how I can do it.

Answer 1

If you want to find any quoted string with c.aspx in it:

/"[^"]*c\.aspx[^"]*"|'[^']*c\.aspx[^']*'/

But really, for parsing most HTML you'd be better off with some sort of DOM parser so that you can be sure what you're matching is really an href.