C# make a window topmost using a window handle

Question

After launching an application using the Process class I'd like to make that window topmost. Currently, my app is the topmost window so when i launch the other app it doesn't display. One thing that came to mind is that I could set topmost = false for my application before launching the process, the problem with this is I want to give the process ample time to load up before displaying it to the user, so I'd like more control over when I switch the other application to the topmost.

Answer 1

You need to use P/Invoke with SetWindowPos to accopmlish this:

[DllImport("user32.dll")]
static extern bool SetWindowPos(IntPtr hWnd, IntPtr hWndInsertAfter, int X, int Y, int cx, int cy, uint uFlags);

static readonly IntPtr HWND_TOPMOST = new IntPtr(-1);
const UInt32 SWP_NOSIZE = 0x0001;
const UInt32 SWP_NOMOVE = 0x0002;
const UInt32 SWP_SHOWWINDOW = 0x0040;

// Call this way:
SetWindowPos(theWindowHandle, HWND_TOPMOST, 0, 0, 0, 0, SWP_NOMOVE | SWP_NOSIZE | SWP_SHOWWINDOW);