C Programming: EOF as a character

Question

When programming C for the command console, what happens when you have a function that tries to use SCANF to ask user input for a CHAR variable, and the user types CTRL+Z (EOF) and hits enter?

For example:

char promptChar()
{
    char c;
    printf("Enter a character: ");
    scanf("%c", &c);
    return c;
}

If the user types CTRL+Z and hits enter, what will promptChar() return? Because if I understand EOF, it's an int.

Answer 1

From the Linux scanf(3) manpage:

"The value EOF is returned if the end of input is reached before either the first successful conversion or a matching failure occurs. EOF is also returned if a read error occurs, in which case the error indicator for the stream (see ferror(3)) is set, and errno is set indicate the error."

Note that this passage concerns the return value of scanf, not the result parameters.

Answer 2

It depends on the command shell you are using, but you really shouldn't be designing any program to expect to read control characters from an interactive prompt.

Most command shells will intercept some of the control characters and use them to tell the shell to do things. For instance ctrl-s and ctrl-q often start and stop the shell's diplay of output characters. ctrl-z on some shells will actually be taken as a command to shut the shell down.

Answer 3

First things first:

SCANF is not defined by the language.
CHAR is not defined by the language.

Ok, with that out of the way ...

The scanf() function returns an integer. That integer is the number of input items assigned or the value of the macro EOF if an input failure occurs before the first conversion.
You didn't check the return value of the scanf() call, so you have no idea what happened. Everything might have worked ok, or the input stream might have ended before the first conversion, or (not for %c) there might have been a conversion failure.

Test the return value of scanf(). Indeed, always test the return value of all <stdio.h> functions.

char ch;
int result = scanf("%c", &ch);
if (result == 1) /* all ok */;
else if (result == 0) /* conversion failure: value of `ch` is indeterminate */;
else if (result == EOF) /* input failure; value of `ch` is indeterminate */;

When the result of the scanf() call is EOF, if you want more information about the reason for input failure, you can use feof() and/or ferror().

else if (result == EOF) {
    if (feof(stdin)) {
        /* no data in input stream */
    }
    if (ferror(stdin)) {
        /* error if input stream (media ejected? bad sector? ...?)
    }
}

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To answer your question: what will promptChar() return?

It will return an indeterminate value of type char.
You could follow the example of library function that deal with characters and return an int from promptChar(). That would be the value of the character read cast to unsigned char or a negative int (EOF) in case of error. Read the description for fgetc(), for instance.