Create single permutation with Linq in C#

Question

I have a code:

    List<int> list = new List<int>();
    for (int i = 1; i <= n; i++)
        list.Add(i);

Can I create this List<int> in one line with Linq?

Answer 1

  List<int> list = Enumerable.Range(1, n).ToList();

Answer 2

List<int> list = Enumerable.Range(1, n).ToList();

Answer 3

If you need a lot of those lists, you might find the following extension method useful:

public static class Helper
{
    public static List<int> To(this int start, int stop)
    {
        List<int> list = new List<int>();
        for (int i = start; i <= stop; i++) {
            list.Add(i);
        }
        return list;
    }
}

Use it like this:

var list = 1.To(5);

Of course, for the general case, the Enumerable.Range thing the others posted may be more what you want, but I thought I'd share this ;) You can use this next time your Ruby-loving co-worker says how verbose C# is with that Enumerable.Range.