This is a very bad idea. Binary data should always be sent in a way that:
- Handles different endianness
- Handles different padding
- Handles differences in the byte-sizes of intrinsic types
Don't ever write a whole struct in a binary way, not to a file, not to a socket.
Always write each field separately, and read them the same way.
You need to have functions like
unsigned char * serialize_int(unsigned char *buffer, int value)
{
/* Write big-endian int value into buffer; assumes 32-bit int and 8-bit char. */
buffer[0] = value >> 24;
buffer[1] = value >> 16;
buffer[2] = value >> 8;
buffer[3] = value;
return buffer + 4;
}
unsigned char * serialize_char(unsigned char *buffer, char value)
{
buffer[0] = value;
return buffer + 1;
}
unsigned char * serialize_temp(unsigned char *buffer, struct temp *value)
{
buffer = serialize_int(buffer, value->a);
buffer = serialize_char(buffer, value->b);
return buffer;
}
unsigned char * deserialize_int(unsigned char *buffer, int *value);
Or the equivalent, there are of course several ways to set this up with regards to buffer management and so on. Then you need to do the higher-level functions that serialize/deserialize entire structs.
This assumes serializing is done to/from buffers, which means the serialization doesn't need to know if the final destination is a file or a socket. It also means you pay some memory overhead, but it's generally a good design for performance reasons (you don't want to do a write() of each value to the socket).
Once you have the above, here's how you could serialize and transmit a structure instance:
int send_temp(int socket, const struct sockaddr *dest, socklen_t dlen,
const struct temp *temp)
{
unsigned char buffer[32], *ptr;
ptr = serialize_temp(buffer, temp);
return sendto(socket, buffer, ptr - buffer, 0, dest, dlen) == ptr - buffer;
}
A few points to note about the above:
- The struct to send is first serialized, field by field, into
buffer
. - The serialization routine returns a pointer to the next free byte in the buffer, which we use to compute how many bytes it serialized to
- Obviously my example serialization routines don't protect against buffer overflow.
- Return value is 1 if the
sendto()
call succeeded, else it will be 0.