Running a command in shell script

Question

Hello

I have a shell script file (run.sh) that contains the following:

#!/bin/bash
%JAVA_HOME%/bin/java -jar umar.jar

when i try to run it (./run.sh), it gives me following: umar/bin/run.sh: line 1: fg: no job control

However if I run same command directly on shell, it works perfectly.

What's wrong with the script file?

Thanks

Answer 1

Try turning on monitor mode

set -m

Answer 2

%foo% is not how you do command substitution in a bourne/BASH shell script. I assume you're running this from a Windows command line, which is why it works when you run it directly. Try using proper bourne syntax:

${JAVA_HOME}/bin/java -jar umar.jar

Answer 3

%JAVA_HOME% will substitute a Windows environment variable and is appropriate in a .bat file.

Try the following shell script which should work on most UNIX like systems.

#!/bin/bash
$JAVA_HOME/bin/java -jar umar.jar