how to implement a property in a interface

Question

i have interface 'IResourcePolicy' contain property Version i have to implemet this property which contain value ,,means in other page i did this type of coding

IResourcePolicy irp(instantiated interface)
irp.WrmVersion = "10.4";

---

Here how can i implement property 'version'

  public interface IResourcePolicy
   {
   string Version
      {
          get;
          set;
      }
}

Answer 1

Interfaces can not contain any implementation (including default values). You need to switch to abstract class.

Answer 2

You mean like this?

class MyResourcePolicy : IResourcePolicy {
    private string version;

    public string Version {
        get {
            return this.version;
        }
        set {
            this.version = value;
        }
    }
}

Answer 3

In the interface, you specify the property:

public interface IResourcePolicy
{
   string Version { get; set; }
}

In the implementing class, you need to implement it:

public class ResourcePolicy : IResourcePolicy
{
   string Version { get; set; }
}

This looks similar, but it is something completely different. In the interface, there is no code, you just specify the there is a property with a getter and a setter, whatever they will do.

In the class, you actually implement them. The shortest way to do this is using this { get; set; } syntax, the compiler will create a field and generate the getter and setter implementation for it.

Answer 4

• but i already assigned values such that irp.WrmVersion = "10.4";

J.Random Coder's answer and initialize version field.

private string version = "10.4';