Template specialization for enum

Question

Is it possible to specialize a templatized method for enums?

Something like (the invalid code below):

template <typename T>
void f(T value);

template <>
void f<enum T>(T value);

In the case it's not possible, then supposing I have specializations for a number of types, like int, unsigned int, long long, unsigned long long, etc, then which of the specializations an enum value will use?

Answer 1

You can use Boost's enable_if with is_enum from Boost.TypeTraits to accomplish this.

In an answer to one of my questions, litb posted a very detailed and well-written explanation of how this can be done.

Answer 2

I'm not sure if I understand your question correctly, but you can instantiate the template on specific enums:

template <typename T>
void f(T value);

enum cars { ford, volvo, saab, subaru, toyota };
enum colors { red, black, green, blue };

template <>
void f<cars>(cars) { }

template <>
void f<colors>(colors) { }

int main() {
    f(ford);
    f(red);
}