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Question

Answer 1

+12 A:

int i = (int)floor(25.342);

AraK 2009-10-27 15:21:21

I'd like the result to be of type int

Manuel 2009-10-27 15:22:23

The problems start when the argument to floor is > INT_MAX or < INT_MIN.

dirkgently 2009-10-27 15:23:55

In that case, you can't actually get an integer version of the floor of the value, so it doesn't really matter.

jprete 2009-10-27 15:30:39

Answer 2

+5 A:

int i = (int)floor(25.342);

Note this will convert 12.99999 to 12.

Ref:

http://www.codecogs.com/reference/c/math.h/floor.php

soru 2009-10-27 15:25:38

Upvoted for reference link, but you don't need the cast to the int there, floor already returns as an int?

Lee 2009-10-27 17:01:54

`floor( )` returns a double (§7.12.9.2 in the C standard).

Stephen Canon 2009-10-27 18:53:46

I sit corrected! Thanks :]

Lee 2009-10-28 17:24:04

Answer 3

+1 A:

Where x is your 25.342

int i = x >= 0 ? (int)(x+0.5) : (int)(x-0.5)

Mike 2009-10-27 15:26:50

@Mike I don't think he wants to round numbers. Look at the negative number example :)

AraK 2009-10-27 15:29:02

I did, his post said "( If it were -12.46 I'd like to get -13)" So I presumed a little rounding.

Mike 2009-10-27 15:33:35

That's rounding to lower, or, essentially, floor().

David Thornley 2009-10-27 15:37:25

Wouldn't rounding -12.46 give you and integer value of -12 and not -13?

semaj 2009-10-27 16:27:41

Not with the check for negativity.

Mike 2009-10-27 16:46:40

Rounding -12.46 to closest integer will produce -12, as will rounding closer to zero. Rounding to lower will give you -13, and this is what the questioner wants.

David Thornley 2009-10-27 16:51:40

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