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323

answers:

1

Hi,

If you run the following code in the Groovy console it prints "8"

class F {

  private final Integer val = 2

  def set(v) {val = v}

  def print() {println val}
}

def f = new F()
f.set(8)
f.print()

In Java this code wouldn't compile because you can't assign a final reference after the constructor has run. I know that for properties, final indicates that the property can't be changed outside the class, but what does it mean to mark a private field final?

Thanks, Don

+1  A: 

It looks like this might be a Groovy bug:

I wouldn't think that val should be assignable after initialization.

Rob Hruska