How to get real bullet positions in MS PowerPoint 2003

Question

Hi, guys.

I'm working on PowerPoint 2003 presentation conversion into some format, and I'm confused very much at one moment. Really, I can't understand what I'm doing wrong for almost two days wasting my time for this i-thought-it-was-tiny problem. I use PowerPoint Object Model to get the presentation document structure and its layout, all the shapes I render are converted with no problems, non-list paragraphs are converted pretty well too. But the text frames with numbered or bulletted lists are dispositioned.

I thought that the following code should work pretty well too. Actually, I've failed:

bulletLeft = currentTextRange.BoundLeft;

currentTextRange.BoundLeft actually returns the position of the bulletted list item text that should be placed here. But I don't understand, I can't understand, etc: how to get X-position of the list item paragraph bullet?

I understand, it's a little problem in real but I'm wasted solving it.
Thank you.

Answer 1

Nevermind, guys. It was my friend's bug on text rendering. The bullet position should be set with the following code:

bulletLeft = shape.Left + shape.TextFrame.MarginLeft;

Sorry for disturbing.

Answer 2

left += Shape.TextFrame.Ruler.Levels[IndentLevel].FirstMargin;