views:

655

answers:

4

Hi Alls,

Im using the SocketServer module for a tcp server. I'm experiencing some issue here with the recv() function, because the incoming packets always have a different size, so if i specify recv(1024) (i tried with bigger value, and smaller), it get stock after 2 or 3 requests because the packet length will be smaller (i think), and then the server get stock until a timeout :( here's my code : ....

class Test(SocketServer.BaseRequestHandler):

def handle(self):

   print "From:", self.client_address

   while True:    

     data = self.request.recv(1024)
     if not data: break

     if data[4] == "\x20":              
       self.request.sendall("hello")
     if data[4] == "\x21":
       self.request.sendall("bye")
     else:
       print "unknow packet"
   self.request.close()
   print "Disconnected", self.client_address

launch = SocketServer.ThreadingTCPServer(('', int(sys.argv[1])),Test)

launch.allow_reuse_address= True;

launch.serve_forever()

The client send multiples requests over the same source port, but the server get stock, any help would be very appreciated, thanks !

A: 

That's the nature of TCP: the protocol fills up packets (lower layer being IP packets) and sends them. You can have some degree of control over the MTU (Maximum Transfer Unit).

In other words: you must devise a protocol that rides on top of TCP where your "payload delineation" is defined. By "payload delineation" I mean the way you extract the unit of message your protocol supports. This can be as simple as "every NULL terminated strings".

jldupont
A: 

The network is always unpredictable. TCP makes a lot of this random behavior go away for you. One wonderful thing TCP does: it guarantees that the bytes will arrive in the same order. But! It does not guarantee that they will arrive chopped up in the same way. You simply cannot assume that every send() from one end of the connection will result in exactly one recv() on the far end with exactly the same number of bytes.

When you say socket.recv(x), you're saying 'don't return until you've read x bytes from the socket'. This is called "blocking I/O": you will block (wait) until your request has been filled. If every message in your protocol was exactly 1024 bytes, calling socket.recv(1024) would work great. But it sounds like that's not true. If your messages are a fixed number of bytes, just pass that number in to socket.recv() and you're done.

But what if your messages can be of different lengths? The first thing you need to do: stop calling socket.recv() with an explicit number. Changing this:

data = self.request.recv(1024)

to this:

data = self.request.recv()

means recv() will always return whenever it gets new data.

But now you have a new problem: how do you know when the sender has sent you a complete message? The answer is: you don't. You're going to have to make the length of the message an explicit part of your protocol. Here's the best way: prefix every message with a length, either as a fixed-size integer (converted to network byte order using socket.ntohs() or socket.ntohl() please!) or as a string followed by some delimiter (like '123:'). This second approach often less efficient, but it's easier in Python.

Once you've added that to your protocol, you need to change your code to handle recv() returning arbitrary amounts of data at any time. Here's an example of how to do this. I tried writing it as pseudo-code, or with comments to tell you what to do, but it wasn't very clear. So I've written it explicitly using the length prefix as a string of digits terminated by a colon. Here you go:

length = None
buffer = ""
while True:
  data += self.request.recv()
  if not data:
    break
  buffer += data
  while True:
    if length is None:
      if ':' not in buffer:
        break
      # remove the length bytes from the front of buffer
      # leave any remaining bytes in the buffer!
      length_str, ignored, buffer = buffer.partition(':')
      length = int(length_str)

    if len(buffer) < length:
      break
    # split off the full message from the remaining bytes
    # leave any remaining bytes in the buffer!
    message = buffer[:length]
    buffer = buffer[length:]
    length = None
    # PROCESS MESSAGE HERE
Larry Hastings
+1  A: 

The answer by Larry Hastings has some great general advice about sockets, but there are a couple of mistakes as it pertains to how the recv(bufsize) method works in the Python socket module.

So, to clarify, since this may be confusing to others looking to this for help:

  1. The bufsize param for the recv(bufsize) method is not optional. You'll get an error if you call recv() (without the param).
  2. The bufferlen in recv(bufsize) is a maximum size. The recv will happily return fewer bytes if there are fewer available.

See the documentation for details.

Now, if you're receiving data from a client and want to know when you've received all of the data, you're probably going to have to add it to your protocol -- as Larry suggests. See this recipe for strategies for determining end of message.

As that recipe points out, for some protocols, the client will simply disconnect when it's done sending data. In those cases, your while True loop should work fine. If the client does not disconnect, you'll need to figure out some way to signal your content length, delimit your messages, or implement a timeout.

I'd be happy to try to help further if you could post your exact client code and a description of your test protocol.

Hans L
A: 

You can alternatively use recv(x_bytes, socket.MSG_WAITALL), which seems to work only on Unix, and will return exactly x_bytes.

henrietta