C# Linq non-vowels

Question

From the given string

(i.e)

string str = "dry sky one two try";
var nonVowels = str.Split(' ').Where(x => !x.Contains("aeiou")); (not working).

How can i extract non-vowel words?

Answer 1

Something like:

var nonVowelWords = str.Split(' ').Where(x => Regex.Match(x, @"[aeiou]") == null);

Answer 2

This should work:

var nonVowels = str.Split(' ').Where(x => x.Intersect("aeiou").Count() == 0);

String.Contains requires you to pass a single char. Using Enumerable.Contains would only work for a single char, as well - so you'd need multiple calls. Intersect should handle this case.

Answer 3

string str = "dry sky one two try";
var nonVowels = str.ToCharArray()
    .Where(x => !new [] {'a', 'e', 'i', 'o', 'u'}.Contains(x));

Answer 4

Come on now y'all. IndexOfAny is where it's at. :)

// if this is public, it's vulnerable to people setting individual elements.
private static readonly char[] Vowels = "aeiou".ToCharArray();

// C# 3
var nonVowelWorks = str.Split(' ').Where(word => word.IndexOfAny(Vowels) < 0);

// C# 2
List<string> words = new List<string>(str.Split(' '));
words.RemoveAll(delegate(string word) { return word.IndexOfAny(Vowels) >= 0; });