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522

answers:

3

I have a XML node with a value which is a white space. Example:

<sampleNode> </sampleNode>

I am using a Serializer to get the data from XML document to store it in an object. Now, the problem I am facing is: If the XML node value contains nothing but a white space, as does the sample node above, the serializer interpretates it as a string.Empty.

How can I overcome this? I need get the actual white space, i.e. " ". Thanks a bunch!

+1  A: 

You can use a CDATA placeholder in order to avoid the removal of the space:

<sampleNode><![CDATA[ ]]></sampleNode>
Laurent Etiemble
Even thought your solution can solve my problem, I will be giving more time to the people to try to overcome the XmlSerializer issue I am facing with a more elegant solution. If however, no one comes up with the better idea, I will mark your answer as correct.
Boris
Have you tried to use the " " entity ? I just though about it.
Laurent Etiemble
+3  A: 

Assuming you are using XmlDocument, you should set the PreserveWhiteSpace property to True.

If using and XmlReader set the WhitespaceHandling property WhitespaceHandling.All.

See this MSDN article about Preserving White Space While Serializing.

The different serializers handle this different ways, try using the XmlTextReader for this, as per this forum post.

Oded
Unfortunately, even though your solution is completely correct, I cannot apply it in my code, as I am not using neither XmlDocument nor XmlReader. I have added my code that converts XML file to an object in the post comment.
Boris
Well, what do you know: I started using XmlReader :D Thanks so much for your answer!
Boris
+1  A: 

Sample class:

using System;

namespace GeneralTesting
{
    [Serializable]
    public class SampleNode
    {
        public string sampleNode = " ";
    }
}

And sample program:

    XmlSerializer xmls = new XmlSerializer(typeof(SampleNode));
    SampleNode sn = new SampleNode();
    using (FileStream fs = File.Open(@"C:\test.xml", FileMode.Create))
    {
        xmls.Serialize(fs, sn);
    }
    using (FileStream fs = File.OpenRead(@"C:\test.xml"))
    {
        XmlReaderSettings xmlrs = new XmlReaderSettings();
        xmlrs.IgnoreWhitespace = false;
        using (XmlReader xmlr = XmlReader.Create(fs, xmlrs))
        {
            Console.WriteLine("!{0}!", ((SampleNode) xmls.Deserialize(xmlr)).sampleNode); //output: ! !
        }
    }
VMAtm
Thank you for your answer and a nice sample on the XmlReader usage.
Boris