pipe many outputs to same file at the same time?

Question

Say i have a bash script:

#!/bin/bash
php ./listen.php 3001 3003 26 &
php ./listen.php 3002 3004 120 &

can i pipe all of them to same output log file at the same time without conflict? example:

#!/bin/bash
php ./listen.php 3001 3003 26 >/tmp/log 2>&1 &
php ./listen.php 3002 3004 120 >/tmp/log 2>&1 &

Answer 1

> overwrites, so you'll want >> instead. stdout is line-buffered by default, so that is relatively safe. stderr is not. You should consider writing to the system log instead though.

Answer 2

Most probably if each write constains new line terminated line.

Hovewer the lines from the both application will be interviling. Just try and see.

Answer 3

Theoretically you can:

#!/bin/bash

{ php ./listen.php 3001 3003 26 & php ./listen.php 3002 3004 120 & } >/tmp/log 2>&1

but I don't know how readable the result will be.