find all subversion working copies on machine

Question

How could I use find unix utility to find all working copies on the machine? For example, I can use find / -name .svn -type d command, but it outputs all redundant results (a lot of subfolders), while I need only parent directory of working copy to be shown.

There is related question, but it does not really help in my case: http://stackoverflow.com/questions/1242364/

Answer 1

Update 3 - sorted output of find to ensure .svn comes before hidden files. still might fail for checked-in hidden directories.

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Perl can remove the nested paths for you:

find -s . -ipath *.svn | perl -lne's!/\.svn$!!i;$a&&/^$a/||print$a=$_'

In human, this says: for each svn path, ignoring the /.svn part, if the current path is a child of the last path I printed, don't print it.

example: for the directory structure:

$ find .
.
./1
./1/.svn
./1/1
./1/1/.svn
./2
./2/.svn
./3

this yields

./1
./2

Answer 2

maybe something like this?

#!/bin/bash
if [ -d "$1/.svn" ]; then
        echo $1
else
        for d in $1/*
        do
                if [ -d "$d" ]; then
                        ( $0 $d )
                fi;
        done
fi;

name it, for example - find_svn.sh, make it executable, and call like ./find_svn.sh /var/www (may need some tweaking to normalize directory name(s), strip trailing slash.. but works for me in this form, when called on some dir without trailing slash).

Answer 3

if you have GNU find/sort

find /path -type f -name ".svn*" -printf "%h\n"  | sort -u