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85

answers:

2
+1  A: 

There are an infinite number of possibilities. Consider a concentric series of circles from the points R and T, representing the distance each could travel at increasing times. Where the circles intersect is the point of collision, a vector between the point of collision and T is where T should have been aimed at for that particular instant. If you are looking for the shortest path, you need to get the normal to R's path and fire T at the appropriate time by calculating the time it takes for T to traverse this distance so it will arrive at the same time as R.

Arthur Kalliokoski
The speed of *T* is fixed (assumption 5), so there are at most 2 possibilities.
KennyTM
A duck hunter shooting a duck with a shotgun can shoot over a wide timeframe even though the speed of the shot isn't affected, right?
Arthur Kalliokoski
Or maybe you're assuming that R and T must be fired at the same instant?
Arthur Kalliokoski
A: 
KennyTM
I only see the speed of R. Where is the speed of T taken into account?
Jacks_Depression
@Jacks: It's defined to be 1. (Change your coordinates system or unit of time if the speed if not 1.)
KennyTM
Here is what I got for the quadratic...http://storage.bja888.com/find-time.pngThe problem is, if the velocity of R is 1 unit/second it will always try to divide by 0. Did I do something wrong?
Jacks_Depression
@Jacks: If *v* = 1 you get 0/0. Make it a special case.
KennyTM