Passing arguments to "make run"

Question

I use MakeFiles.

I have a target called "run" which runs the build target. Simplified, it looks like:

prog: ....
  ...

run: ./prog
  ./prog

Sit back down. I know this is ingenious, but no need for an standing ovation.

Now, question is -- is there anyway to pass arguments? So hat

make run asdf --> ./prog asdf
make run the dog kicked the cat --> ./prog the dog kicked the cat

Thanks!

Answer 1

for standard make you can pass arguments by defining macros like this

make run arg1=asdf

then use them like this

run: ./prog $(arg1)
   etc

References for make Microsoft's NMake

Answer 2

I don't know a way to do what you want exactly, but a workaround might be:

run: ./prog
    ./prog ${ARGS}

Then:

make ARGS="asdf" run

Answer 3

No. Looking at the syntax from the man page for GNU make

make [ -f makefile ] [ options ] ... [ targets ] ...

you can specify multiple targets, hence 'no' (at least no in the exact way you specified).

Answer 4

anon, run: ./prog looks a bit strange, as right part should be a target, so run: prog looks better.

I would suggest simply:

.PHONY: run

run:
        prog $(arg1)

and I would like to add, that arguments can be passed:

1. as argument: make arg1="asdf" run
2. or be defined as environment: arg1="asdf" make run