showing list item in python

Question

Hello,

I want to manipulate feed which contains frequently updated (with time) contents using feed parser. Goal is to show all the contents of the updated feed.

import feedparser
d = feedparser.parse("some URL")

print "Information of user" 
i = range(10)

for i in d:
    print d.entries[i].summary 

print " " 

As parsing data is list, and list don't accept string as indices, it shows error

like:

File "F:\JavaWorkspace\Test\src\rss_parse.py", line 18, in <module>
print d.entries[i].summary 
TypeError: list indices must be integers

Then how can I get all contents? can anyone please show me some light on this issue? Thanks in advance!

Answer 1

i is not an integer. I guess i is already an entry of the feed but better rename it:

Try:

for entry in d.entries:
  print entry.summary

If you want the first 10 entries you have to do:

try:
  for i in range(10):
    print d.entries[i].summary
except IndexError:
  pass

Answer 2

You first assign a list of integers to i (i = range(10)) and then just lose the reference to this list. Are you sure you didn't mean:

r = range(10)

for i in r:

or simply:

for i in range(10):

Answer 3

for i in range(10):
    print d.entries[i].summary

Answer 4

for all entries make:

import feedparser
d = feedparser.parse("some URL")

print "Information of user" 

for i in range(len(d['entries'])):
    print d.entries[i].summary 

print " "

Answer 5

import feedparser
from StringIO import StringIO
d = feedparser.parse("some URL")
buff = StringIO()
print >>buff, "Information of user" 

for i,e in enumerate(d.entries):
    print >>buff, i, e.summary 

print >>buff," "
print buff

If you need the index, I suggest also to use a String Buffer to do I/O operations on big string.

Answer 6

Say you want to print the 10 first elements of the list if there is 10 or more, or what it contains otherwise. Felix allready proposed a working solution with exception management. You could also use itertools like below.

import feedparser
d = feedparser.parse('http://feedparser.org/docs/examples/atom10.xml')

from itertools import islice

for elt in islice(d.entries, 1, 10):
    print elt.summary

What is nice with islice is that if you want to access to elements from say 3 to 10 (a slice) it also works as easily. Just have to replace 1 with 3. It also works with step if you want say only even elements, etc.