Get the nth item of a generator in Python

Question

Is there a more syntactically concise way of writing the following?

gen = (i for i in xrange(10))
index = 5
for i, v in enumerate(gen):
    if i is index:
        return v

It seems almost natural that a generator should have a gen[index] expression, that acts as a list, but is functionally identical to the above code.

Answer 1

Perhaps you should elaborate more on a actual use case.

>>> gen = xrange(10)
>>> ind=5 
>>> gen[ind]
5

Answer 2

one method would be to use itertools.islice

>>> next(itertools.islice(xrange(10), 5, 5 + 1))
5

Answer 3

You could do this, using count as an example generator:

from itertools import islice, count
islice(count(), n, n+1).next()