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117

answers:

2

I have some C code, where in there are two linked lists(say A and B) and A is inserted at a particular position into B and A still has elements.

How do I simulate the same behavior effectively using the C++ STL? If I try splice, it makes the second one empty.

Thanks, Gokul.

+1  A: 

You need to copy the elements. Consider something like this:

std::copy(a.begin(), a.end(), std::inserter(b, b_iterator));

If you want the same nodes shared by two lists, this is simply not supported by std::list (STL containers always have exclusive ownership). You can avoid duplicating the elements by storing pointers in the list, or by using boost::ptr_list, which internally stores pointers but offers a nicer API.

Tronic
Thanks. I just wanted to confirm that.
Gokul
Note that is is potentially slower than the other solution (http://stackoverflow.com/questions/2349098/2349119#2349119). See the comments at http://stackoverflow.com/questions/2551775/2551808#2551808 for why that is.
sbi
+5  A: 

Try insert:

B.insert( position, A.begin(), A.end() );

to insert copies of the elements of A in B before 'position'. A itself remains unchanged. See this link

ArunSaha
+1 better answer than mine.
Tronic
@Tronic: Thank you.
ArunSaha