How to use a pipe in a foreach statement

Question

I have a for loop I'd like to run in bash like:

for i in user_* do; cat $i | ./fetch_contact.php ; done;

Always gives an error like

-bash: syntax error near unexpected token `done'

I assume it has something to do with the pipe, but nothing I try to add in (parenthesis, etc) wrap the pipe sufficiently. How do you use a pipe in a command like this?

Answer 1

foreach i in user_*; do cat $i | ./fetch_contact.php ; done;

Semicolon should go before do, not after.

Answer 2

Turns out getting the semicolons and everything else right makes this whole pipe thing moot.

for i in user_*; do cat $i | ./fetch_contact.php; done;

Answer 3

In Bash, do is a command. Also, it is for not foreach. Here's the fix:

for i in user_*; do cat $i | ./fetch_contact.php; done;

Answer 4

Why loop?

cat user_* | ./fetch_contact.php

Answer 5

No need for cat:

for i in user_* ; do ./fetch_contact.php < "$i" ; done

Answer 6

here's one with some checking

for file in user_*
do
  if [ -f "$file" ];then
    ./fetch_contact.php < "$file"
  fi
done