Why gives the following Windows 7 .cmd command script:
set SUN_JAVA_HOME=C:\Program Files (x86)\Java\jdk1.6.0_17
if 3==3 (
set JAVA_HOME=%SUN_JAVA_HOME%
)
echo ready
The following error message instead of printing "ready"
\Java\jdk1.6.0_17 was unexpected at this time.
The error message disapears, if I remove the "(x86)" in the path name.