PHP: get number of decimal digits

Question

Hi!

Is there a straightforward way of determining the number of decimal places in a(n) integer/double value in PHP? (that is, without using explode)

Thanks,

Erwin

Answer 1

You could try casting it to an int, subtracting that from your number and then counting what's left.

Answer 2

Something like:

<?php

$floatNum = "120.340304";
$length = strlen($floatNum);

$pos = strpos($floatNum, "."); // zero-based counting.

$num_of_dec_places = ($length - $pos) - 1; // -1 to compensate for the zero-based count in strpos()

?>

This is procedural, kludgy and I wouldn't advise using it in production code. But it should get you started.

Answer 3

$str = "1.23444";
print strlen(substr(strrchr($str, "."), 1));

Answer 4

$decnumber = strlen(strstr($yourstr,'.'))-1

Answer 5

function numberOfDecimals($value)
{
    if ((int)$value == $value)
    {
        return 0;
    }
    else if (! is_numeric($value))
    {
        // throw new Exception('numberOfDecimals: ' . $value . ' is not a number!');
        return false;
    }

    return strlen($value) - strrpos($value, '.') - 1;
}


/* test and proof */

function test($value)
{
    printf("Testing [%s] : %d decimals\n", $value, numberOfDecimals($value));
}

foreach(array(1, 1.1, 1.22, 123.456, 0, 1.0, '1.0', 'not a number') as $value)
{
    test($value);
}

Outputs:

Testing [1] : 0 decimals
Testing [1.1] : 1 decimals
Testing [1.22] : 2 decimals
Testing [123.456] : 3 decimals
Testing [0] : 0 decimals
Testing [1] : 0 decimals
Testing [1.0] : 0 decimals
Testing [not a number] : 0 decimals

Answer 6

I have a 50% solution to your question, I will try and write the other half later if I have time:

function num_decimals($number) {
    if(is_int($number))
        return 0;
    throw new Exception("TODO");
}