ansaurus

Question

Answer 1

A:

grep MemTotal /proc/meminfo | awk '{print $2}'

The returned number is in KB

Neuquino 2010-03-14 03:15:00

it seems you have answered your own question. nevertheless, use one awk command to do the job. `awk '/MemTotal/{print $2}' /proc/meminfo`

ghostdog74 2010-03-14 04:53:10

Answer 2

A:

How about

var=$(free | awk '/^Mem:/{print $2}')

kiwicptn 2010-03-14 04:12:16

no spaces between "=" sign when assigning variable. use `$()` syntax wherever possible.

ghostdog74 2010-03-14 04:52:15

@ghostdog74: thanks (post fixed)

kiwicptn 2010-03-14 05:01:08

grep _and_ awk?

Tadeusz A. Kadłubowski 2010-03-16 09:57:29

@Tadeusz: thanks (post fixed)

kiwicptn 2010-03-16 22:45:08

Answer 3

+1 A:

phymem=$(awk -F":" '$1~/MemTotal/{print $2}' /proc/meminfo )

or using free

phymem=$(free|awk '/^Mem:/{print $2}')

or using shell

#!/bin/bash

while IFS=":" read -r a b
do
  case "$a" in
   MemTotal*) phymem="$b"
  esac
done <"/proc/meminfo"
echo $phymem

ghostdog74 2010-03-14 04:31:41

How to get physical memory in bash