+1  A: 

Character 10 (0xa) is the Ascii code for linefeed, which many *nix operating systems use for line terminator. It should not be part of the filename. Just strip it off. Also, such operating systems use 0 for a string terminator. It should be at the end of the filename unless the open call takes a number of characters parameter.

The solution is to take the user's reply, find character 10 and replace it with zero. Use the result as the filename to open.

wallyk  2010-04-04 21:08:26
Thank youI have solved the problem, by writing and calling the following procedure<pre><code>nameClean: li $t0, 0 #loop counter li $t1, 21 #loop endclean: beq $t0, $t1, L5 lb $t3, fin($t0) bne $t3, 0x0a, L6 sb $zero, fin($t0) L6: addi $t0, $t0, 1j cleanL5:jr $ra</code></pre>
Hassan Al-Jeshi  2010-04-04 21:21:11
A: 

Where did you put that code?! Great Program dude! Congrats.

Unkwnon  2010-04-20 23:42:26
Thank you very much. I put that code at the end of the file. And I have called the procedure just after I ask the user to input the file name
Hassan Al-Jeshi  2010-04-21 12:47:37

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