views:

73

answers:

5

I want to search for the occurrence of string1 OR string2 OR string3, etc. in a file, and print only those lines (to stdout or a file, either one). How can I easily do this in bash?

+5  A: 
grep "string1\|string2\|string3" file_to_search_in
Chen Levy
Thanks, Chen, for your speedy reply. Of course, that works - slick!
topwoman
Perhaps you could accept his answer also, if it works.
Anders
A: 

Also:

grep -e 'string1' -e 'string2' -e 'string3'
Randy Proctor
Thanks, Randy, worked like a charm!And, meanwhile, I found one more:egrep 'string1|string2' infile
topwoman
+2  A: 

you can also use awk

awk '/string1|string2|string3/' file

With awk, you can also easily use AND logic if needed.

awk '/string1/ && /string2/ && /string3/' file
ghostdog74
+1  A: 

With Perl:

perl -lne 'print if /string1|string2|string3/;' file1 file2 *.fileext

With Bash one liner:

while read line; do if [[ $line =~ string1|string2 ]]; then echo $line; fi; done < file

With Bash script:

#!/bin/bash

while read line
do
    if [[ $line =~ string1|string2|string3 ]]; then
       echo $line
    fi
done < file 

Note that the spaces around "[[ $line =~ string1|string2 ]]" are all relevant. ie these fail in Bash:

[[ $line=~string1|string2 ]] # will be alway true...
[[$line =~ string1|string2]] # syntax error
drewk
The curly braces can be omitted from your Bash one liner. The `do` and `done` do that for you.
Dennis Williamson
do elim_curly_braces; done!
drewk
+1  A: 

There are many acceptable answers already, but one other choice, especially if the number of strings you want to search is large, is to put those strings into a file, delimited by newlines and use

grep -f file_of_strings file_to_search

frankc