views:

311

answers:

2

Hi,

I have a database with lets assume two columns (service_date & invoice_amount). I would like to create an SQL query that would retrieve and group the data for each financial year (July to June).

I have two years of data so that is two financial years (i.e. 2 results).

I know I can do this manually by creating an SQL query to group by month then run the data through PHP to create the financial year data but I'd rather have an SQL query.

All ideas welcome.

Thanks

A: 

This works for me in MSSQL.. Hope it works for you in MySQL

SELECT
   CASE WHEN MONTH(service_date)>=7 THEN
           YEAR(service_date)+1 
   ELSE YEAR(service_date) END AS financial_year,
   SUM(invoice_amount)
FROM mytable
GROUP BY
   CASE WHEN MONTH(service_date)>=7 THEN
           YEAR(service_date)+1 
   ELSE YEAR(service_date)
CResults
+1  A: 
SELECT
   CASE WHEN MONTH(service_date)>=7 THEN
          concat(YEAR(service_date), '-',YEAR(service_date)+1)
   ELSE concat(YEAR(service_date)-1,'-', YEAR(service_date)) END AS financial_year,
   SUM(invoice_amount)
FROM mytable
GROUP BY financial_year

which produce o/p like below

financial_year   invoice_amount
2007-2008        10000.00
2008-2009        15000.00
2009-2010        20000.00
Salil
Hey its uncanny, how did you know his table was called mytable too? And you used financial_year with an underscore..
CResults
Salil
@Salil Thanks for your help mate. Works perfectly.
mlevit