gcc run "light" preprocessor

Question

Is there any way to run the gcc preprocessor, but only for user-defined macros? I have a few one-liners and some #ifdef etc... conditionals, and I want to see what my code looks like when just those are expanded. As it is, the includes get expanded, my fprintf(stderr)s turn into fprintf(((__getreeent())->_stderr), etc...

Answer 1

Call cpp directly, e.g.

$ cat >foo.c <<EOF
#define FOO
#ifdef FOO
foo is defined
#else
foo is not defined
#endif
EOF

$ cpp foo.c
# 1 "foo.c"
# 1 "<built-in>"
# 1 "<command-line>"
# 1 "foo.c"


foo is defined

Of course, if you include any headers then those will be included in the output. One way to avoid that might be to just grep -v out the lines with #includes (or perhaps just ones with #include < and allow #include "). Or you could specify the -nostdinc option to remove just standard includes (but possibly leave in local libraries unless you specify include paths so that they won't be found) - this would warn about missing headers, though.

Edit: Or use the preprocessor itself to make the inclusion of headers conditional, wrap them in something like #ifndef TESTING_PREPROCESSOR and use -DTESTING_PREPROCESSOR.

Answer 2

cpp -nostdinc program.c

Answer 3

gcc  -E inputfile.c > outputfile.c

outputfile.c will have your preprocessed code, but all macros will be expanded.

I find this trick very useful when debugging compilation of large systems with tons of includes, compiler flags, and makefile variables. It will expose include files that don't have header guards, and a bunch of other problems too.