views:

150

answers:

1

Using SQL Server 2008, Visual Studio 2005, .net 2.0 with SP2 (has support for new SQL Server 2008 data types).

I'm trying to write an SQLCLR function that takes a DateTime2 as input and returns another DateTime2. e.g. :

using System;
using System.Data.SqlTypes;
using Microsoft.SqlServer.Server;

namespace MyCompany.SQLCLR
{
    public class DateTimeHelpCLR
    {
        [SqlFunction(DataAccess = DataAccessKind.None)]
        public static SqlDateTime UTCToLocalDT(SqlDateTime val)
        {
            if (val.IsNull)
                return SqlDateTime.Null;

            TimeZone tz = System.TimeZone.CurrentTimeZone;
            DateTime res = tz.ToLocalTime(val.Value);

            return new SqlDateTime(res);
        }
    }
}

Now, the above compiles fine. I want these SqlDateTimes to map to SQL Server's DateTime2, so I try to run this T-SQL :

CREATE function hubg.f_UTCToLocalDT
(
    @dt DATETIME2
)
returns DATETIME2
AS
EXTERNAL NAME [SQLCLR].[MyCompany.SQLCLR.DateTimeHelpCLR].UTCToLocalDT
GO

This gives the following error :

Msg 6551, Level 16, State 2, Procedure f_UTCToLocalDT, Line 1 CREATE FUNCTION for "f_UTCToLocalDT" failed because T-SQL and CLR types for return value do not match.

Using DATETIME (instead of DATETIME2) works fine. But I'd rather use DATETIME2 to support the increased precision. What am I doing something wrong, or is DateTime2 not (fully) supported by SQLCLR ?

+2  A: 

You need to change the DateTime types in the signature of your Function Method. SQLDateTime maps to a DateTime on the database.

System.DateTime is more precise and can be mapped to DateTime2 (but by default, it'll be dropped as a DateTime in the deploy script).

[SqlFunction(DataAccess = DataAccessKind.None)]
//OLD Signature public static SqlDateTime UTCToLocalDT(SqlDateTime val) 
public static DateTime UTCToLocalDT(DateTime val) {
   ...
}

Then you can tweak your deploy script to read.

CREATE FUNCTION [UTCToLocalDT]
(
    @dt [datetime2]
)
RETURNS [datetime2]
AS
    EXTERNAL NAME [SQLCLR].[MyCompany.SQLCLR.DateTimeHelpCLR].UTCToLocalDT
GO

Running your function should now give you more precise output.

DECLARE @input DateTime2, @output DateTime2
SET @input = '2010-04-12 09:53:44.48123456'
SET @output = YourDatabase.dbo.[UTCToLocalDT](@input)
SELECT @input, @output
Eoin Campbell
Thanks for that. Does this technique support passing and returning NULLs ?
Moe Sisko