xsl literal with <xsl:if>

Question

Hi, I have to write a very simple code in xsl: IF column=0 if result = .34 set background color to green and write $result, but if result = 0.10 set background color to white and write the word "QQQ" and what doesn't work is:

<xsl:if test="$result  = 0.35 and $column = 0">
    <xsl:attribute name='background-color'>#669933</xsl:attribute>
    <xsl:value-of select="result"/>      
</xsl:if>

<xsl:if test="$result = 0.10">
    <xsl:value-of select="QQQ"/>
</xsl:if>

any suggestions? thanks in advance

Answer 1

<xsl:if test="$result  = 0.35 and $column = 0">    
    <xsl:attribute name='background-color'>#669933</xsl:attribute>

    <xsl:value-of select="result"/>          
</xsl:if>    

<xsl:if test="$result = 0.10">    
    <xsl:value-of select="QQQ"/>    
</xsl:if>

You have committed exactly two errors in the code above.

Here is the corrected version:

 <xsl:if test="$result  = 0.35 and $column = 0">
   <xsl:attribute name='background-color'>#669933</xsl:attribute>
   <xsl:value-of select="$result"/>
 </xsl:if>

 <xsl:if test="$result = 0.10">
   <xsl:value-of select="'QQQ'"/>
 </xsl:if>

The errors are:

1. result means the elements named result that are children of the context node. You want the <xsl:variable> named result. By definition the name of any referenced <xsl:variable> should be prefixed by the $ character.

2. <xsl:value-of select="QQQ"/> selects all children of the current node named QQQ and outputs the string value of the first of them. You want just the string 'QQQ' to be produced. By definition, to distinguish a string from a name, the string must be enclosed in quotes or in apostrophes.