Bash script: regexp reading numerical parameters from text file

Question

Greetings!

I have a text file with parameter set as follows:

---

NameOfParameter Value1 Value2 Value3 ... ...

---

I want to find needed parameter by its NameOfParameter using regexp pattern and return a selected Value to my Bash script. I tried to do this with grep, but it returns a whole line instead of Value.

Could you help me to find as approach please?

Answer 1

It was not clear if you want all the values together or only one specific one. In either case, use the power of cut command to cut the columns you want from a file (-f 2- will cut columns 2 and on (so everything except parameter name; -d " " will ensure that the columns are considered to be space-separated as opposed to default tab-separated)

egrep '^NameOfParameter ' your_file | cut -f 2- -d " "

Answer 2

Bash:

values=($(grep '^NameofParameter '))
echo ${values[0]}    # NameofParameter 
echo ${values[1]}    # Value1
echo ${values[2]}    # Value2
# etc.

for value in ${values[@:1]}    # iterate over values, skipping NameofParameter
do
    echo "$value"
done

Answer 3

OK, thank you guys!

Is there any way in Linux to return only and exactly that part of text that mached a regexp?