How do I sort a list of python Django objects?

Question

In Django, I have a model object in a list.

[object, object, object]

Each object has ".name" which is the title of the thing.

How do I sort alphabetically by this title?

This doesn't work:

catlist.sort(key=lambda x.name: x.name.lower())

Answer 1

catlist.sort(key=lambda x: x.name.lower())

Answer 2

Without the call to lower(), the following could be considered slightly cleaner than using a lambda:

import operator
catlist.sort(key=operator.attrgetter('name'))

Add that call to lower(), and you enter into a world of function-composition pain. Using Ants Aasma's compose() found in an answer to this other SO question, you too can see the light that is FP:

>>> def compose(inner_func, *outer_funcs):
...     if not outer_funcs:
...         return inner_func
...     outer_func = compose(*outer_funcs)
...     return lambda *args, **kwargs: outer_func(inner_func(*args, **kwargs))
...
>>> class A(object):
...   def __init__(self, name):
...     self.name = name
...
>>> L = [A(i) for i in ['aa','a','AA','A']]
>>> name_lowered = compose(operator.attrgetter('name'), 
                           operator.methodcaller('lower'))
>>> print [i.name for i in sorted(L, key=name_lowered)]
['a', 'A', 'aa', 'AA']