C# Why does this code not show a GUI properly?

Question

class Program
{
    static String ChannelName = null;
    static Form1 f;

    static void Main()
    {
        f = new Form1();
        f.Show();
        try
        {
            MY CODE WHICH CALLS INTO ANOTHER CLASS BUT CANNOT PASS THE GUI INSTANCE AS
            IT USES REMOTING
        }
    }
}

I know this isnt the best/normal way to do it, but i need to write data to the GUI from a class which has bo instance of the GUI so i was going to call Program.method() and use a function to write to the GUI in program. However when i run the above my GUI displays but with the windows hourglass?

Could someone show me a quick fix so that i can still crudely show the GUI, let the application code run and then later write to the GUI?

Answer 1

You could move your try block to the Form.Shown event to allow your form to be shown before it begins processing.

Answer 2

You need to call the Form.ShowDialog method.

    static void Main(string[] args)
    {
        f = new Form1();

        try
        {
            f.label1.Text = "Changed Label from Console!";
            f.textBox1.Text = "Changed Textbox from Console!";
        }
        catch (Exception)
        {

            throw;
        }

        f.ShowDialog();
    }

Should make it work.

Answer 3

Hey guys i did it in the end! I put my GUI creation into a thread and gave my gui class a methodinvoker which allows me to use a delegate to write to it from another thread.

My data class calls a method in program, which sends the string to write to the methodinvoker in the gui and wala!

Thanks for your ideas and help!