Why System.Boolean takes 4 bytes even if it just stores one state TRUE or FALSE; which may be stored less than 4 bytes?
The first result on a Google search for System.Boolean size told me that it's to do with memory alignment. It's faster to push around a four-byte Int32 than it is to work with individual bytes/bits.
Because it's fast.
A 32-bit processor typically works with 32-bit values. Working with smaller values involves longer instructions, or extra logic.
I think it's only for performance, 32 bit values are much more efficient to manipulate.
Where'd you get that? System.Boolean takes only 1 byte.
Just try:
Console.WriteLine( sizeof( System.Boolean ).ToString() );
A bool
is actually only 1 byte, but alignment may cause 4 bytes to be used on a 32-bit platform, or even 8 bytes on a 64-bit platform. For example, the Nullable<bool>
(aka bool?
) type uses a full 32 or 64 bits—depending on platform—even though it's comprised of just two bool
s. EDIT: As pointed out by Jon Skeet, padding for alignment isn't always present. As an example, an array of Nullable<bool>
s takes only 2 bytes per object instead of 4 or 8.
But even 8 bits to represent a bool
can be considered wasteful if you have many of them to store. For this reason, if you create a type that has many bool
s as members, (or uses many Nullable<>
types), and users of your class might create many instances of it, you might consider using a BitVector32
instead. The framework itself uses this technique to reduce the memory footprint of many of the Windows Forms controls, for instance.
sorry
it prints 4 byte:) bool b=false; Console.WriteLine(System.Runtime.InteropServices.Marshal.SizeOf(b).ToString());
also I don`t understand that...
// char type prints 2 byte
Console.WriteLine( sizeof( System.char ).ToString() );
// prints 1 byte
char c='@'; Console.WriteLine( sizeof( c ).ToString() );