windows bat file: how to strip the path-part from a absolute filepath

Question

hello

i have a variable like this:

set file=c:\dir\foo\bar\file.txt

how can i get just the path-part into another variable?

echo %pathpart%

should give c:\dir\foo\bar\

thanks!

Answer 1

http://stackoverflow.com/questions/778135/how-do-i-get-the-equivalent-of-dirname-in-a-batch-file