views:

32

answers:

1

I have this snippet of the code:

 set calls = `cut -d" " -f2 ${2} | grep -c "$numbers"`
 set messages = `cut -d" " -f2 ${3} | grep -c "$numbers"`

 @ popularity = (calls * 3) + messages

and error

@ expression syntax

what does it mean? grep -c returns number, am I wrong, thanks in advance

in $numbers I have list of numbers, 2 and 3 parameters also contain numbers

A: 

Try

@ popularity = ($calls * 3) + $messages

The $ symbols are still needed to indicate variables.

See C-shell Cookbook

Damien Ayers