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Returning PHP Multi-Dimension Array to Javascript/AJAX

Answer 1

A:

<?php

$twoDArr = array( array('Greg', 44, 'Owner'),
                  array('Joe', 23, 'Renter'),
                  array('Susan', 39, 'Owner'),
                  array('John', 32, 'Renter)
                );
?>

<script>
twoDArr = JSON.parse(<?=json_encode($twoDArr)?>)
alert(twoDArr[0][0]) //alerts 'Greg'
alert(twoDArr[0][1]) //alerts '44'
alert(twoDArr[1][0]) //alerts 'Joe'
</script>

tipu 2010-06-07 01:52:04

While this example certainly works, it is generally best to avoid eval when a simple alternative is present. In this case, you could replace the eval statement with JSON.parse(<?=json_encode($twoDArr)?>) to achieve the same effect.

Rookwood 2010-06-07 02:04:23

@Rockwood: I edited my answer to reflect your suggestion

tipu 2010-06-07 02:11:45

Sorry for being so obtuse...you have "JSON.parse(<?=json_encode($twoDArr)?>)" What's with the "?=" is that some sort of shorthand? I tried this in my sample page and I get nothing coming back.

GregH 2010-06-07 18:45:46

Something weird is up...if I echo out json_encode($twoDArr) I get:[["Greg",44,"Owner"],["Joe",23,"Renter"],["Susan",39,"Owner"],["John",32,"Renter"]] That isn't right is it? Should the arrays be separated by a ":"?

GregH 2010-06-07 19:26:55

Ok, I figured out the problem. I'm not sure why, but the php variable has to be double encoded with JSON_ENCODE. So the JSON.parse line should read: var twoDArr=JSON.parse(<?php echo JSON_ENCODE(JSON_ENCODE($twoDArr))?>);

GregH 2010-06-07 20:50:08

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Returning PHP Multi-Dimension Array to Javascript/AJAX

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