phpexcel write excel and save ?

Question

code:
<?php
    /** PHPExcel */
    require_once '../Classes/PHPExcel.php';
    /** PHPExcel_IOFactory */
    require_once '../Classes/PHPExcel/IOFactory.php';

    // Create new PHPExcel object
    $objPHPExcel = new PHPExcel();

    // Set properties
    $objPHPExcel->getProperties()->setCreator("Maarten Balliauw")
                         ->setLastModifiedBy("Maarten Balliauw")
                         ->setTitle("Office 2007 XLSX Test Document")
                         ->setSubject("Office 2007 XLSX Test Document")
                         ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.")
                         ->setKeywords("office 2007 openxml php")
                         ->setCategory("Test result file");
    $result = 'select * from table1';
    for($i=0;$i<count($result);$i++){
       $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id'];
       for ($j=0;$j<count($result1);$j++) {
       $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']);
       }
       // Set active sheet index to the first sheet, so Excel opens this as the first sheet
       $objPHPExcel->setActiveSheetIndex(0);

       // Save Excel 2007 file
       $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007');
       $objWriter->save(str_replace('.php', '.xlsx', __FILE__));

      // Echo done
      echo date('H:i:s') . " Done writing file.\r\n";

    }
?>

The above code executes and save n no of .xlsx files in the folder, but the problem im getting is biggest count(result1) in the for loop executing in all saved excel files. Please give me the solution.

Answer 1

You will want mysql_num_rows - http://php.net/manual/en/function.mysql-num-rows.php

$q = 'select * from table1';
$res = mysql_query($q);
$count = mysql_num_rows($result);

for ($j=0;$j<$count;$j++) {
    #code here
}

you may also want to look at mysql_fetch_assoc

Answer 2

Before going deep, one thing is clear

You haven't executed the query for $result, neither fetch it and on $result1 query you are using it which is not possible,

Same problem exist with $result1

You can use:

$result = mysql_query('select * from table1');
while($fetch_result=mysql_fetch_array($result))
{
    $result2 = mysql("select * from table2 where table1_id = '".$fetch_result['table1_id']."'");

   while($fetch_result2=mysql_fetch_array($result2)
   {
    --your code--

But it is preferable to write JOIN instead of these two query