tags:

views:

132

answers:

5

Is there any way to set explicit type to object field in php? Something like this

class House{
       private Roof $roof
}
+7  A: 

Nope, there isn't. PHP variables can always be of any type. But you can enforce a type in the setter:

public function setRoof(Roof $roof) {
  $this->roof = $roof;
}
JW
Note that you can only enforce objects or arrays, but not "primitive" types like float or string.
svens
Had you a setter that expected a primitive type, `bool` for example, you could always `assert('is_bool($value)');`.
meagar
@svens: FWIW, PHP development added scalar type hinting on 5/20/2010. I'm not sure when that will make it into an official release, though.
Bill Karwin
Didn't know, thanks.
svens
A: 

Why not just assign $roof to a new Roof()?

Gnostus
Excuse me what?
dimo414
+1  A: 

You're looking for PHP's Type Hinting. It works great on function/method calls. Here's the manual:

http://php.net/manual/en/language.oop5.typehinting.php

CaseySoftware
+4  A: 

You can't use PHP code to declare the type of an object field.

But you can put type hints in docblock comments:

class House{
       /**
        * @var Roof
        */
       private $roof
}

This still doesn't make the code enforce types, but some IDE tools understand the docblocks and may warn you if you use this variable without conforming to the type hint.

Bill Karwin
A: 

you could also use the following before using the member

if (!$this->roof instanceof Roof) {

    throw new Exception('$this->roof is not an instance of Roof');
}
zolex