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51

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2

Lets say i have a python script at homedir/codes/py/run.py I also have a bash script at homedir/codes/run.sh This bash script runs run.py by python py/run.py.

The thing is that i need to be able to find out, in run.py, the path to the calling script run.sh. If run.sh is run from its own directory, i can just use os.getcwd(). But run.sh can in principle be run from anywhere, and then os.getcwd() will return the path to where run.sh is run FROM, and not the actual location of run.sh.

ex:

  • At homedir/codes: ./run.sh -> os.getcwd() returns homedir/codes
  • At homedir: ./codes/run.sh -> os.getcwd() returns homedir

But i want homedir/codes no matter how run.sh is called. Is this possible?

+1  A: 

To get the absolute path of the current script in bash, do:

SCRIPT=$(readlink -f "$0")

Now, pass that variable as the last argument to the python script. You can get the argument from python as:

sys.argv[-1]
fmark
Another way of getting the current directory of the running bash script (with dirname command within backticks): SCRIPT='dirname $0'
John P
This mostly works, but is nonportable, see http://mywiki.wooledge.org/BashFAQ/028. `$0`, like all parameters, should always be quoted.
Philipp
If you don't want to pass parameters, it should also be possible to set the directory you want in the shell wrapper.
Mattias Nilsson
+2  A: 

you can get the absolute qualified path with:

os.path.join(os.path.abspath(os.curdir))
bharling
This isn't want the OP wants.
fmark