How to turn an image's file path into the actual image?

Question

Hello,

I've saved a user's respective picture in a folder named 'profileportraits'. So when a user uploads their picture, it is saved into that folder. Furthermore, I also save the 'portrait path', i.e. the location/name of the photo onto a MySQL database for user data. My question is: I am able to echo the Portrait Path, where the user's portrait is stored onto the page. But how will I display the actual photo onto the page? I.e. how can I turn the file path into the actual picture? Will I have to match the path that I retrieved from MySQL to the directory? or something else? Below is a bit of code.

{
echo $row['PortraitPath'];
}

With the code above, I am able to echo the actual path, which is: profileportraits/DSC00310.JPG. I simply want to turn this path of the picture, into the actual picture. Thank you.

Answer 1

<img src="<?php echo $row['PortraitPath']; ?>" />

or

<?php
echo "<img src=\"{$row['PortraitPath']}\" />";
?>

Answer 2

Why not use the path as the source of an image tag:

echo "<img src=\"{$row['PortraitPath']}\" />"

Answer 3

from the 2 code that Brendan mentioned, I prefer the 1st one

<img src="<?php echo $row['PortraitPath']; ?>" />

as that will get colorized/highlighted better in notepad++