sed + how to get the second word (string) after "=" separator by sed

Question

hi

how to get the second word (string) after "=" separator by sed (need to ignore spaces)

for example

   echo " bla bla word word1 = strin1 string2 " | sed .....

I should get string2

another example

    echo " bla bla word word1 =swhsw 123  " | sed .....

I should get 123

please advice lidia

Answer 1

I believe awk is a better solution for this case, simply use.

echo "bla bla word word1 = strin1 string2" | awk -F"=" '{print $2}' | awk '{print $2}'

Answer 2

$ echo " bla bla word word1 = strin1 string2 " | sed 's/.[^=]*=\(.[^ \t]*\)[ \t]*\(.[^ \t]*\)\(.*\)/\2/'
string2


$ echo " bla bla word word1 =swhsw 123  " | awk -F"=" '{split($2,a," ");print a[2]}'
123

And how about you start reading up on how to use sed/awk ?